Geometry · Grade 10

Modeling with Geometry: Shapes, Density and Design

Quick answer

A tree trunk is not a cylinder and a torso is not a cylinder, yet treating them as one answers questions about volume to within a few percent. Density turns a geometric measure into a count or a weight — people per square mile, pounds per cubic foot. And a design problem asks for the shape that meets a constraint at the lowest cost.

What you'll learn

  • Choose a geometric shape to model a physical object
  • Apply density based on area and volume
  • Solve a design problem under a constraint

Replacing an object with a shape

No real object is a geometric solid. A tree trunk tapers, a silo has a lip, a can has a rim. Measuring any of them exactly is a job for a scanner.

Modeling replaces the object with a shape close enough to answer the question.

ObjectModelQuestion it answers
Tree trunkcylinderhow much lumber it holds
Grain silocylinder with a hemisphere on tophow much grain it stores
Soup cancylinderhow much metal it takes
Camping tenttriangular prismhow much air is inside
Human torsocylinderroughly how much skin area
Countypolygonpopulation per square mile

The model is chosen for the question, not for looks. A trunk modeled as a cylinder answers a volume question well and a bark-texture question not at all.

Density in two dimensions

Density is an amount divided by the space it occupies. In two dimensions that space is an area.

population density=peoplearea\text{population density} = \frac{\text{people}}{\text{area}}

A city of 86,00086{,}000 people covering 2424 square miles has

86,00024≈3,583 people per square mile\frac{86{,}000}{24} \approx 3{,}583 \text{ people per square mile}

Dividing by area is what makes two places comparable. A county with more people than another may be less crowded, and only the density says so.

Density in three dimensions

In three dimensions the space is a volume, and the quantity is usually mass or energy.

density=massvolume⟹mass=density×volume\text{density} = \frac{\text{mass}}{\text{volume}} \qquad\Longrightarrow\qquad \text{mass} = \text{density} \times \text{volume}
QuantityUnitsTypical use
Mass densitypounds per cubic footweight of a load of gravel
Energy densityBTUs per cubic footheat from natural gas
Concentrationmilligrams per litera contaminant in water

The pattern is the same every time: geometry supplies the volume, density supplies the rest.

Why a rough shape still gives a usable number

Treating a tapered trunk as a straight cylinder looks careless. It is not, and the reason is worth stating.

A model’s error in volume tracks its error in shape. A trunk whose radius varies by 10%10\% over its length gives a volume within roughly 20%20\% of the cylinder’s. That is the worst case, because the fat end and the thin end pull in opposite directions and partly cancel.

So the model answers “about how much lumber?” and refuses to answer “exactly how much?” That is the right division of labor. The question that gets asked in practice is the first one, because the second requires equipment the first one makes unnecessary.

Two habits keep a rough model honest.

Bracket it. Compute with the largest plausible measurement and the smallest. If both answers lead to the same decision, the model is good enough.

Say which way it errs. A cylinder around a tapered trunk overestimates, because the cylinder is as wide as the widest point everywhere.

Design problems

The third use of geometry is to choose a shape rather than measure one. A design problem fixes a requirement and asks for the cheapest, lightest or smallest way to meet it.

A standard soda can holds 355355 cm³. The metal used is its total surface area.

V=πr2h=355⟹h=355πr2V = \pi r^2 h = 355 \qquad\Longrightarrow\qquad h = \frac{355}{\pi r^2} S=2πr2+2πrh=2πr2+710rS = 2\pi r^2 + 2\pi r h = 2\pi r^2 + \frac{710}{r}

The first term grows with rr and the second shrinks, so somewhere between them the total bottoms out.

Radius (cm)Height (cm)Metal (cm²)
2.52.518.0818.08323.3323.3
3.03.012.5612.56293.2293.2
3.53.59.229.22279.8279.8
3.843.847.677.67277.5277.5
4.04.07.067.06278.0278.0
4.54.55.585.58285.0285.0
Metal used by a 355 cm³ can A curve of total surface area against radius, falling steeply, flattening to a lowest point near a radius a little under four centimeters, then rising again. 1234567100200300400500xy least metal
  • surface area, cm²
Metal used by a 355 cm³ can

The least-metal can has r≈3.84r \approx 3.84 and h≈7.67h \approx 7.67, and those two numbers are related:

h=2rh = 2r

The cheapest can is exactly as tall as it is wide. That result holds for every volume, not only 355355 cm³.

A real soda can is taller and narrower than that. The shape is not a mistake — it is a different problem. A narrow can fits a hand, holds a label that can be read, and has a thicker top and bottom than its side, which shifts where the minimum falls.

A constraint instead of a cost

Some design problems fix a limit rather than a price. Ramps built to the American accessibility standard rise at most 11 inch for every 1212 inches of run.

Worked examples

Common mistakes

Practice problems

  1. Which solid best models a soup can?

    Answer

    A cylinder.

    Full solution

    The can has a circular base and straight vertical sides, which is what a cylinder is.

  2. Which model fits a grain silo with a domed top?

    Answer

    A cylinder with a hemisphere on top.

    Full solution

    The straight walls are a cylinder and the dome is half a sphere, so the volumes add.

  3. A county has 240,000240{,}000 people spread over 800800 square miles. Find the population density.

    Answer

    300300 people per square mile.

    Full solution

    240,000800=300\tfrac{240{,}000}{800} = 300.

  4. A block of wood measuring 2 ft×1 ft×0.5 ft2 \text{ ft} \times 1 \text{ ft} \times 0.5 \text{ ft} weighs 3333 pounds. Find its density.

    Answer

    3333 pounds per cubic foot.

    Full solution

    The volume is 2×1×0.5=12 \times 1 \times 0.5 = 1 cubic foot, so the density is 331=33\tfrac{33}{1} = 33 pounds per cubic foot.

  5. A porch is 2424 inches above the ground. At a rise of 11 inch per 1212 inches of run, how long must the ramp’s run be?

    Answer

    288288 inches, or 2424 feet.

    Full solution

    24×12=28824 \times 12 = 288 inches, and 28812=24\tfrac{288}{12} = 24 feet.

  6. A tree trunk measures 5050 inches around, with 3030 feet of usable length. Estimate its volume in cubic feet.

    Hint

    Convert the radius to feet before using it.

    Answer

    About 4141 cubic feet.

    Full solution

    r=502π≈7.96r = \tfrac{50}{2\pi} \approx 7.96 inches, which is 0.6630.663 feet.

    V=π(0.663)2(30)≈41.4V = \pi(0.663)^2(30) \approx 41.4 cubic feet.

    Two significant figures is as much as one tape measurement supports, so about 4141 cubic feet.

  7. A pool is 2525 feet by 1515 feet and 44 feet deep throughout. At 7.487.48 gallons per cubic foot, how many gallons does it hold?

    Answer

    About 11,22011{,}220 gallons.

    Full solution

    V=25×15×4=1,500V = 25 \times 15 \times 4 = 1{,}500 cubic feet.

    1,500×7.48=11,2201{,}500 \times 7.48 = 11{,}220 gallons.

  8. From the table in this lesson, which radius gives a 355355 cm³ can the least metal, and what is special about its shape?

    Answer

    About 3.843.84 cm, where the height equals the diameter.

    Full solution

    The metal column bottoms out at 277.5277.5 cm² when r=3.84r = 3.84, and the height there is 7.677.67, which is 2r2r.

  9. Explain why a real soda can is taller and narrower than the least-metal shape.

    Answer

    Metal cost is one constraint among several — grip, label space, and thicker ends all push the shape taller.

    Full solution

    The calculation minimizes metal alone, and assumes the metal is the same thickness everywhere.

    A real can has a thicker top and bottom to survive stacking and pressure, so the two circular ends cost more per square centimeter than the side. That alone shifts the cheapest shape toward a narrower can with smaller ends.

    The rest is human. A can as wide as it is tall is awkward to hold and gives a label almost no readable height.

    The lesson generalizes: a design problem with one constraint has a clean answer, and a real product balances several.

  10. A conical pile of road salt is 1212 feet across at the base and 66 feet tall. Asked for its volume, Rosa computes π(6)2(6)≈678.6\pi(6)^2(6) \approx 678.6 cubic feet. Find her error.

    Hint

    Which solid did she compute?

    Answer

    She used the cylinder formula. A cone holds a third as much: about 226.2226.2 cubic feet.

    Full solution

    Her radius of 66 is right, since 1212 feet across gives a radius of 66.

    The formula is not. πr2h\pi r^2 h is the cylinder that the pile fits inside, and a cone fills exactly a third of it.

    V=13π(6)2(6)=72π≈226.2V = \tfrac{1}{3}\pi(6)^2(6) = 72\pi \approx 226.2 cubic feet

    The error shows up in any sanity check. A cone of salt cannot hold as much as a drum of the same width and height, because most of that drum is air above the slope.

Frequently asked questions

What does it mean to model an object with a shape?

Replacing the object with a shape whose measurements are close enough that the answer you need comes out right, even though the object is not that shape.

What is population density?

People divided by area, usually people per square mile. It turns a raw population into a number that compares places of different sizes.

How do I find mass from density and volume?

Multiply. Density is mass per unit volume, so mass equals density times volume.

What shape uses the least metal for a can of fixed volume?

The one whose height equals its diameter. For a 355 cm³ can that means a radius of about 3.84 cm and a height of about 7.67 cm.

Why are real soda cans taller than that?

Metal cost is one constraint among several. A taller can is easier to hold, gives more room for printing, and the thicker top and bottom change the arithmetic.

Standards alignment

This lesson covers the following Common Core State Standards for Mathematics.

  • CCSS.MATH.CONTENT.HSG.MG.A.1Modeling with GeometryUse geometric shapes, their measures, and their properties to describe objects (e.g., modeling a tree trunk or a human torso as a cylinder).
  • CCSS.MATH.CONTENT.HSG.MG.A.2Modeling with GeometryApply concepts of density based on area and volume in modeling situations (e.g., persons per square mile, BTUs per cubic foot).
  • CCSS.MATH.CONTENT.HSG.MG.A.3Modeling with GeometryApply geometric methods to solve design problems (e.g., designing an object or structure to satisfy physical constraints or minimize cost; working with typographic grid systems based on ratios).