Precalculus · Grades 11, 12

Adding, Subtracting and Scaling Vectors

Quick answer

Vectors add end to end: follow one arrow, then the next, and the sum is the arrow from the first start to the last finish. In components that is plain addition. The length of a sum is usually shorter than the two lengths added, because the arrows point different ways. Subtracting adds the reversed vector, and multiplying by a number stretches, shrinks or reverses an arrow.

What you'll learn

  • Add and subtract vectors end to end, by components and by the parallelogram rule
  • Add vectors given by magnitude and direction
  • Multiply a vector by a scalar and find the result's magnitude and direction

Adding end to end

Walk 44 blocks east and 11 north, then 11 east and 33 north. Where have you ended up, compared with where you started?

Each walk is a vector: v=⟨4,1⟩\mathbf{v} = \langle 4, 1\rangle and w=⟨1,3⟩\mathbf{w} = \langle 1, 3\rangle. Doing one after the other means starting w\mathbf{w} where v\mathbf{v} ends. The total trip, the sum, runs from the first start to the last finish.

Adding v and w end to end From the origin, an arrow v to (4, 1), then an arrow w from (4, 1) to (5, 4). A third arrow, in a second color, runs straight from the origin to (5, 4): the sum. Dashed copies of w from the origin and v from (1, 3) complete a parallelogram. v w v + w 246246xy
Adding v and w end to end

In components, the moves across add and the moves up add:

⟨4,1⟩+⟨1,3⟩=⟨5,4⟩\langle 4, 1\rangle + \langle 1, 3\rangle = \langle 5, 4\rangle

The dashed arrows show the same sum reached the other way round, w\mathbf{w} first. The two routes form a parallelogram, and the sum is its diagonal. That is the parallelogram rule, and it shows the order does not matter:

v+w=w+v\mathbf{v} + \mathbf{w} = \mathbf{w} + \mathbf{v}

Why the length of a sum is not the sum of the lengths

v\mathbf{v} is about 4.124.12 long and w\mathbf{w} about 3.163.16. Their sum, ⟨5,4⟩\langle 5, 4\rangle, is about 6.406.40 long — not 7.287.28.

The three arrows form a triangle, and one side of a triangle is always shorter than the other two combined. Going straight from start to finish is shorter than detouring through the corner.

∥v+w∥≤∥v∥+∥w∥\lVert\mathbf{v} + \mathbf{w}\rVert \le \lVert\mathbf{v}\rVert + \lVert\mathbf{w}\rVert

The two sides match only when the arrows point the same way, and the triangle flattens into a line. Pushes in different directions partly work against each other, which is exactly what the shorter sum records.

Adding vectors given by magnitude and direction

When vectors come as a size and a direction, convert each to components, add, then convert back.

A plane heads due north at 300300 miles per hour. A wind blows due east at 5050 miles per hour. What is the plane’s actual velocity?

⟨0,300⟩+⟨50,0⟩=⟨50,300⟩\langle 0, 300\rangle + \langle 50, 0\rangle = \langle 50, 300\rangle speed=502+3002≈304.1 mph\text{speed} = \sqrt{50^2 + 300^2} \approx 304.1 \text{ mph}

The direction is east of north by the angle whose tangent is 50300\tfrac{50}{300}: about 9.46°9.46°. The wind both speeds the plane slightly and pushes it off course.

Subtraction reverses an arrow

−w-\mathbf{w} has the same length as w\mathbf{w} and points the opposite way. Subtracting is adding the reverse:

v−w=v+(−w)\mathbf{v} - \mathbf{w} = \mathbf{v} + (-\mathbf{w})

In components the minus signs do it: ⟨4,1⟩−⟨1,3⟩=⟨3,−2⟩\langle 4, 1\rangle - \langle 1, 3\rangle = \langle 3, -2\rangle.

On a diagram, with both arrows starting together, v−w\mathbf{v} - \mathbf{w} is the arrow from the tip of w\mathbf{w} to the tip of v\mathbf{v} — because w\mathbf{w} plus that arrow gets you to v\mathbf{v}.

v − w runs from the tip of w to the tip of v Arrows v to (4, 1) and w to (1, 3) both start at the origin. A third arrow, in a second color, runs from (1, 3), the tip of w, to (4, 1), the tip of v. v w v − w -1123456-1123456xy
v − w runs from the tip of w to the tip of v

Scaling a vector

Multiplying a vector by a number cc, a scalar, multiplies each component:

c⟨a,b⟩=⟨ca,cb⟩c\langle a, b\rangle = \langle ca, cb\rangle

The length is multiplied by ∣c∣\lvert c\rvert:

∥cv∥=∣c∣ ∥v∥\lVert c\mathbf{v}\rVert = \lvert c\rvert\,\lVert\mathbf{v}\rVert

The direction stays the same when c>0c > 0 and reverses when c<0c < 0.

Scaling v by 2 and by −1 From the origin, an arrow v to (2, 1), a longer arrow in the same direction to (4, 2) labeled 2v, and an arrow pointing the opposite way to (-2, -1) labeled minus v. 2v v −v -4-224-4-224xy
Scaling v by 2 and by −1

Worked examples

Common mistakes

Practice problems

  1. Find ⟨3,−2⟩+⟨1,6⟩\langle 3, -2\rangle + \langle 1, 6\rangle.

    Answer

    ⟨4,4⟩\langle 4, 4\rangle

    Full solution

    Add across and up separately: ⟨3+1,−2+6⟩\langle 3 + 1, -2 + 6\rangle.

  2. Find ⟨5,1⟩−⟨2,4⟩\langle 5, 1\rangle - \langle 2, 4\rangle.

    Answer

    ⟨3,−3⟩\langle 3, -3\rangle

    Full solution

    ⟨5−2,1−4⟩=⟨3,−3⟩\langle 5 - 2, 1 - 4\rangle = \langle 3, -3\rangle.

  3. Find −2⟨1,3⟩-2\langle 1, 3\rangle and describe its direction.

    Answer

    ⟨−2,−6⟩\langle -2, -6\rangle, pointing opposite to ⟨1,3⟩\langle 1, 3\rangle.

    Full solution

    Each component is multiplied by −2-2. The negative scalar reverses the direction and doubles the length.

  4. If ∥v∥=5\lVert\mathbf{v}\rVert = 5, find ∥−3v∥\lVert -3\mathbf{v}\rVert.

    Answer

    1515

    Full solution

    ∣−3∣⋅5=15\lvert -3\rvert \cdot 5 = 15.

  5. Compare ∥⟨3,0⟩+⟨0,4⟩∥\lVert\langle 3, 0\rangle + \langle 0, 4\rangle\rVert with ∥⟨3,0⟩∥+∥⟨0,4⟩∥\lVert\langle 3, 0\rangle\rVert + \lVert\langle 0, 4\rangle\rVert.

    Answer

    55 and 77

    Full solution

    The sum is ⟨3,4⟩\langle 3, 4\rangle, of length 55. The lengths 33 and 44 add to 77. The arrows are at right angles, so the straight path is shorter.

  6. Add forces of 66 newtons east and 88 newtons north. Give the size and direction of the total.

    Answer

    1010 newtons, about 53.13°53.13° north of east.

    Full solution

    ⟨6,8⟩\langle 6, 8\rangle has length 1010, and its direction satisfies tan⁡θ=86\tan\theta = \tfrac{8}{6}, so θ≈53.13°\theta \approx 53.13°.

  7. A plane heads north at 300300 mph with a 5050 mph wind blowing east. Find its actual speed.

    Answer

    About 304.1304.1 mph

    Full solution

    ⟨0,300⟩+⟨50,0⟩=⟨50,300⟩\langle 0, 300\rangle + \langle 50, 0\rangle = \langle 50, 300\rangle, of length 92,500≈304.1\sqrt{92{,}500} \approx 304.1.

  8. A boat heads north at 88 mph across a river flowing east at 33 mph. At what angle east of north does it actually travel?

    Answer

    About 20.56°20.56°

    Full solution

    The velocity is ⟨3,8⟩\langle 3, 8\rangle. The angle from north satisfies tan⁡θ=38\tan\theta = \tfrac{3}{8}, so θ≈20.56°\theta \approx 20.56°.

  9. With v\mathbf{v} and w\mathbf{w} both drawn from the origin, where does the arrow for v−w\mathbf{v} - \mathbf{w} start and end?

    Answer

    From the tip of w\mathbf{w} to the tip of v\mathbf{v}.

    Full solution

    Adding that arrow to w\mathbf{w}, tip to tail, lands on the tip of v\mathbf{v}. So it is the vector that, added to w\mathbf{w}, gives v\mathbf{v}, which is v−w\mathbf{v} - \mathbf{w}.

  10. Two ropes pull a sled with 55 pounds of force each, one due east and one due north. Kofi says the total pull is 1010 pounds. Find his error.

    Hint

    Do the two ropes point the same way?

    Answer

    He added magnitudes of vectors at right angles. The total is 52≈7.075\sqrt{2} \approx 7.07 pounds, at 45°45°.

    Full solution

    The pulls are ⟨5,0⟩\langle 5, 0\rangle and ⟨0,5⟩\langle 0, 5\rangle, which sum to ⟨5,5⟩\langle 5, 5\rangle.

    Its length is 25+25=52≈7.07\sqrt{25 + 25} = 5\sqrt{2} \approx 7.07 pounds, pointing northeast.

    The two ropes partly pull in different directions, so less of each pull goes toward the combined direction. Only ropes pulling the same way would give 1010.

Frequently asked questions

How do I add two vectors?

Add their components: ⟨a, b⟩ + ⟨c, d⟩ = ⟨a + c, b + d⟩. On paper, place the second arrow's start at the first arrow's tip; the sum runs from the first start to the second tip.

Is the magnitude of a sum the sum of the magnitudes?

Only when the vectors point the same way. Otherwise the sum is shorter, as the third side of a triangle is shorter than the other two combined.

What is v − w?

v + (−w), where −w has the same length as w and points the opposite way. On a diagram it is the arrow from the tip of w to the tip of v.

What does multiplying a vector by a number do?

It multiplies the length by the number's absolute value. A positive number keeps the direction; a negative one reverses it.

How do I add vectors given as a magnitude and a direction?

Convert each to components, add the components, then convert the sum back to a magnitude and a direction.

What to learn next

Standards alignment

This lesson covers the following Common Core State Standards for Mathematics.

  • CCSS.MATH.CONTENT.HSN.VM.B.4Vector and Matrix Quantities(+) Add and subtract vectors.
  • CCSS.MATH.CONTENT.HSN.VM.B.4aVector and Matrix QuantitiesAdd vectors end-to-end, component-wise, and by the parallelogram rule. Understand that the magnitude of a sum of two vectors is typically not the sum of the magnitudes.
  • CCSS.MATH.CONTENT.HSN.VM.B.4bVector and Matrix QuantitiesGiven two vectors in magnitude and direction form, determine the magnitude and direction of their sum.
  • CCSS.MATH.CONTENT.HSN.VM.B.4cVector and Matrix QuantitiesUnderstand vector subtraction v - w as v + (-w), where -w is the additive inverse of w, with the same magnitude as w and pointing in the opposite direction. Represent vector subtraction graphically by connecting the tips in the appropriate order, and perform vector subtraction component-wise.
  • CCSS.MATH.CONTENT.HSN.VM.B.5Vector and Matrix Quantities(+) Multiply a vector by a scalar.
  • CCSS.MATH.CONTENT.HSN.VM.B.5aVector and Matrix QuantitiesRepresent scalar multiplication graphically by scaling vectors and possibly reversing their direction; perform scalar multiplication component-wise, e.g., as c(v<sub>x</sub>, v<sub>y</sub>) = (cv<sub>x</sub>, cv<sub>y</sub>).
  • CCSS.MATH.CONTENT.HSN.VM.B.5bVector and Matrix QuantitiesCompute the magnitude of a scalar multiple cv using ||cv|| = |c|v. Compute the direction of cv knowing that when |c|v ? 0, the direction of cv is either along v (for c > 0) or against v (for c < 0).