Precalculus · Grades 11, 12

The Complex Plane: Polar Form and Geometric Operations

Quick answer

A complex number a + bi can be drawn as the point (a, b). The same point can also be named by its distance from the origin and its angle, which is polar form. Adding complex numbers slides points like arrows placed end to end. Multiplying them multiplies their distances and adds their angles, which turns hard powers into short ones, and the distance between two numbers is the size of their difference.

What you'll learn

  • Plot complex numbers and convert between rectangular and polar form
  • Represent addition, conjugation and multiplication geometrically
  • Find the distance and midpoint between two complex numbers

Complex numbers as points

A complex number a+bia + bi carries two real numbers, so it fits naturally on a plane. The real part goes across and the imaginary part goes up.

3+4i  ⟷  (3,4)3 + 4i \;\longleftrightarrow\; (3, 4)

Real numbers sit on the horizontal axis, and numbers like 2i2i sit on the vertical axis. Every complex number has exactly one point, and every point is exactly one complex number.

3 + 4i and its conjugate on the complex plane The complex plane with a segment from the origin to the point 3 plus 4i, 5 units long, and the conjugate 3 minus 4i reflected across the real axis. -6-4-2246-6-4-2246ReIm 3 + 4i 3 − 4i
3 + 4i and its conjugate on the complex plane

Polar form: a distance and an angle

The same point can be located a second way: how far it is from the origin, and in which direction.

The distance is the modulus, written ∣z∣|z|:

∣a+bi∣=a2+b2∣3+4i∣=9+16=5|a + bi| = \sqrt{a^2 + b^2} \qquad |3 + 4i| = \sqrt{9 + 16} = 5

The direction is the argument θ\theta, the angle from the positive real axis. For 3+4i3 + 4i it is about 53.13°53.13°.

A point at distance rr in direction θ\theta has coordinates (rcos⁡θ,rsin⁡θ)(r\cos\theta, r\sin\theta) — the unit circle scaled up by rr. So

a+bi=r(cos⁡θ+isin⁡θ)a + bi = r(\cos\theta + i\sin\theta)

Both forms name the same point, because a=rcos⁡θa = r\cos\theta and b=rsin⁡θb = r\sin\theta are two descriptions of one location: one by how far across and up, the other by how far out and at what angle.

Adding, subtracting and conjugating

Adding adds the real parts and the imaginary parts separately, which is exactly how arrows add: place one after the other.

(3+i)+(1+2i)=4+3i(3 + i) + (1 + 2i) = 4 + 3i
Adding complex numbers places arrows end to end Arrows from the origin to 3 plus i and to 1 plus 2i, and a parallelogram completed by dashed sides, with its far corner at the sum, 4 plus 3i. -1123456-1123456ReIm 3 + i 1 + 2i 4 + 3i
Adding complex numbers places arrows end to end

The sum is the far corner of the parallelogram built on the two arrows. Subtraction reverses one arrow: z−wz - w is the arrow that goes from ww to zz.

The conjugate of a+bia + bi is a−bia - bi, the reflection of the point across the real axis, as the first figure shows.

Why multiplying multiplies lengths and adds angles

Multiply two numbers in polar form:

r1(cos⁡α+isin⁡α)⋅r2(cos⁡β+isin⁡β)r_1(\cos\alpha + i\sin\alpha) \cdot r_2(\cos\beta + i\sin\beta)

Expand, using i2=−1i^2 = -1:

r1r2[(cos⁡αcos⁡β−sin⁡αsin⁡β)+i(sin⁡αcos⁡β+cos⁡αsin⁡β)]r_1 r_2\bigl[(\cos\alpha\cos\beta - \sin\alpha\sin\beta) + i(\sin\alpha\cos\beta + \cos\alpha\sin\beta)\bigr]

The two brackets are exactly the sum formulas:

=r1r2(cos⁡(α+β)+isin⁡(α+β))= r_1 r_2\bigl(\cos(\alpha + \beta) + i\sin(\alpha + \beta)\bigr)

Multiplying complex numbers multiplies their moduli and adds their arguments. Every multiplication is a stretch combined with a rotation.

Multiplying by ii, which has modulus 11 and argument 90°90°, is a pure quarter turn: i(3+4i)=−4+3ii(3 + 4i) = -4 + 3i, the point (3,4)(3, 4) rotated 90°90° counterclockwise.

Powers by angle and length

Powers repeat the rule. Take w=−1+3 iw = -1 + \sqrt{3}\,i: its modulus is 1+3=2\sqrt{1 + 3} = 2 and its argument is 120°120°. Cubing it cubes the modulus and triples the angle:

w3=23(cos⁡360°+isin⁡360°)=8(1+0i)=8w^3 = 2^3\bigl(\cos 360° + i\sin 360°\bigr) = 8(1 + 0i) = 8

Expanding (−1+3 i)3(-1 + \sqrt{3}\,i)^3 by hand gives the same 88, after considerably more work.

Distance and midpoint

The distance between two complex numbers is the length of the arrow from one to the other, which is the modulus of their difference:

distance=∣z−w∣\text{distance} = |z - w|

The midpoint is their average:

midpoint=z+w2\text{midpoint} = \frac{z + w}{2}

These are the distance and midpoint formulas of the coordinate plane, written in complex numbers.

Worked examples

Common mistakes

Practice problems

  1. Find ∣5−12i∣|5 - 12i|.

    Answer

    1313

    Full solution

    25+144=169=13\sqrt{25 + 144} = \sqrt{169} = 13.

  2. Write 2+23 i2 + 2\sqrt{3}\,i in polar form.

    Answer

    4(cos⁡60°+isin⁡60°)4(\cos 60° + i\sin 60°)

    Full solution

    r=4+12=4r = \sqrt{4 + 12} = 4. The point (2,23)(2, 2\sqrt{3}) satisfies cos⁡θ=24=12\cos\theta = \tfrac{2}{4} = \tfrac{1}{2} with a positive height, so θ=60°\theta = 60°.

  3. Write 6(cos⁡90°+isin⁡90°)6(\cos 90° + i\sin 90°) in rectangular form.

    Answer

    6i6i

    Full solution

    6cos⁡90°=06\cos 90° = 0 and 6sin⁡90°=66\sin 90° = 6.

  4. Add (2+5i)+(4−3i)(2 + 5i) + (4 - 3i) and describe the addition on the plane.

    Answer

    6+2i6 + 2i, the far corner of the parallelogram on the two arrows.

    Full solution

    Add real parts and imaginary parts: 6+2i6 + 2i. On the plane, the arrow to 4−3i4 - 3i is placed at the tip of the arrow to 2+5i2 + 5i.

  5. Find the conjugate of −3+7i-3 + 7i and describe it on the plane.

    Answer

    −3−7i-3 - 7i, the reflection across the real axis.

    Full solution

    Conjugating negates the imaginary part, which flips the point over the horizontal axis.

  6. Compute i(3+4i)i(3 + 4i) and describe what happened to the point.

    Answer

    −4+3i-4 + 3i; the point turned 90°90° counterclockwise.

    Full solution

    3i+4i2=−4+3i3i + 4i^2 = -4 + 3i. Multiplying by ii adds 90°90° to the argument and leaves the modulus at 55.

  7. Find (−1+3 i)3(-1 + \sqrt{3}\,i)^3.

    Hint

    Find the modulus and argument first.

    Answer

    88

    Full solution

    The modulus is 22 and the argument is 120°120°. Cubing gives modulus 88 and argument 360°360°, which is the positive real number 88.

  8. Find the distance between 1+2i1 + 2i and 4+6i4 + 6i.

    Answer

    55

    Full solution

    ∣(4+6i)−(1+2i)∣=∣3+4i∣=5|(4 + 6i) - (1 + 2i)| = |3 + 4i| = 5.

  9. Find the midpoint of −2+5i-2 + 5i and 6−i6 - i.

    Answer

    2+2i2 + 2i

    Full solution

    (−2+6)+(5−1)i2=4+4i2=2+2i\tfrac{(-2 + 6) + (5 - 1)i}{2} = \tfrac{4 + 4i}{2} = 2 + 2i.

  10. Maya says ∣3+4i∣=7|3 + 4i| = 7, since ∣3∣=3|3| = 3 and ∣4i∣=4|4i| = 4. Find her error.

    Hint

    Draw the two arrows, 33 and 4i4i, end to end.

    Answer

    The modulus is a distance, found with the Pythagorean theorem: ∣3+4i∣=5|3 + 4i| = 5.

    Full solution

    The arrow for 33 points right and the arrow for 4i4i points up. Placed end to end they are the legs of a right triangle, and the sum 3+4i3 + 4i is the hypotenuse, from the origin to (3,4)(3, 4).

    Its length is 32+42=5\sqrt{3^2 + 4^2} = 5. Lengths only add when the arrows point the same way.

Frequently asked questions

How do I plot a complex number?

Treat a + bi as the point (a, b): the real part across and the imaginary part up. 3 + 4i sits at (3, 4).

What is polar form?

r(cos θ + i sin θ), where r is the distance from the origin, called the modulus, and θ is the angle from the positive real axis, called the argument.

What does multiplying complex numbers do geometrically?

It multiplies their moduli and adds their arguments. Multiplying by i, which has modulus 1 and argument 90°, rotates a point a quarter turn counterclockwise.

How do I find the distance between two complex numbers?

Subtract them and take the modulus of the difference. The distance between z and w is |z − w|.

What is the conjugate on the plane?

The reflection across the real axis. The conjugate of a + bi is a − bi.

What to learn next

Standards alignment

This lesson covers the following Common Core State Standards for Mathematics.

  • CCSS.MATH.CONTENT.HSN.CN.B.4The Complex Number System(+) Represent complex numbers on the complex plane in rectangular and polar form (including real and imaginary numbers), and explain why the rectangular and polar forms of a given complex number represent the same number.
  • CCSS.MATH.CONTENT.HSN.CN.B.5The Complex Number System(+) Represent addition, subtraction, multiplication, and conjugation of complex numbers geometrically on the complex plane; use properties of this representation for computation.
  • CCSS.MATH.CONTENT.HSN.CN.B.6The Complex Number System(+) Calculate the distance between numbers in the complex plane as the modulus of the difference, and the midpoint of a segment as the average of the numbers at its endpoints.