Algebra 1 · Grade 9

Exponential Functions: Growth by a Constant Factor

Quick answer

A linear function adds the same amount each step. An exponential function multiplies by the same factor each step. That single difference decides which model a situation needs — a flat $50 a month is linear, 5% a month is exponential — and it is why exponential growth eventually passes any line, however steep.

What you'll learn

  • Tell a linear situation from an exponential one
  • Read the start value and growth factor from a table or a rule
  • Explain why exponential growth passes any linear growth

Adding versus multiplying

Two savings plans, both starting at $100.

MonthPlan A: add $50Plan B: add 50%
00100100100100
11150150150150
22200200225225
33250250337.50337.50
44300300506.25506.25

Plan A adds the same amount every month. Plan B multiplies by the same factor every month.

Plan A: +50 each monthPlan B: ×1.5 each month\text{Plan A: } +50 \text{ each month} \qquad \text{Plan B: } \times 1.5 \text{ each month}

Plan A is linear. Plan B is exponential. They agree for one month and then separate for good.

The two tests

Given a table with evenly spaced inputs, two subtractions and two divisions settle which model applies.

TestLinearExponential
difference between outputsconstantnot constant
ratio between outputsnot constantconstant

For Plan A the differences are 50,50,50,5050, 50, 50, 50 — constant, so linear.

For Plan B the ratios are 1.5,1.5,1.5,1.51.5, 1.5, 1.5, 1.5 — constant, so exponential.

The same distinction shows in words:

DescriptionModel
$50 a monthlinear — a fixed amount per step
5%5\% a monthexponential — a fixed percent per step
3030 miles per hourlinear
doubles every 33 daysexponential
loses $2{,}000 of value a yearlinear
loses 15%15\% of its value a yearexponential

A fixed amount is linear; a fixed percent is exponential. A percent is a multiplication, and repeated multiplication is what exponential means.

The form

y=a⋅bxy = a \cdot b^x
PartMeaning
aathe value at x=0x = 0 — the starting amount
bbthe growth factor — the multiplier for each step of 11
xxthe number of steps

Plan B above is:

y=100⋅1.5xy = 100 \cdot 1.5^x

At x=0x = 0 that gives 100⋅1=100100 \cdot 1 = 100, because anything to the power 00 is 11. The start value is always the yy-intercept, which makes it readable straight off a graph.

The exponent counts the multiplications, so 1.531.5^3 is three months of growth. That is the whole content of the formula.

Growth, decay and the value of b

bbBehavior
b>1b > 1growth — the amount rises
b=1b = 1constant — nothing changes
0<b<10 < b < 1decay — the amount falls

A percent change converts to bb directly:

b=1+rb = 1 + r

A rise of 5%5\% gives b=1.05b = 1.05. A fall of 15%15\% gives b=0.85b = 0.85, since 1−0.15=0.851 - 0.15 = 0.85.

Multiplying by 0.850.85 and subtracting 15%15\% are the same operation. Keeping 85%85\% of something is what losing 15%15\% of it means.

Why exponential always wins eventually

A line with a huge slope beats a slow exponential for a while. It never beats it forever.

Exponential growth overtaking a steep line A grid with two curves from 0 to 6 across and 0 to 40 up. A straight line rises steadily through (0, 0), (2, 10) and (4, 20). A curve starts lower at (0, 1), stays below the line until about x = 4, then turns sharply upward and passes it, reaching 32 at x = 5. 12345610203040xy
  • y = 5x
  • y = 2^x
Exponential growth overtaking a steep line

At x=4x = 4 the line is at 2020 and the curve is at 1616. One step later the line is at 2525 and the curve is at 3232.

The reason is structural. The line adds a fixed amount per step; the curve adds a fixed fraction of a total that is itself growing. Once that total is large enough, one step of the curve adds more than the line’s entire step — and it keeps getting worse for the line.

220=1,048,5765(20)=1002^{20} = 1{,}048{,}576 \qquad 5(20) = 100

The same argument beats x2x^2, x3x^3 and any polynomial. Nothing that grows by addition keeps up with something that grows by multiplication.

Worked examples

Changing the time step

A growth factor belongs to a time step — per year, per month, per hour. The exponent rule (bm)n=bmn(b^m)^n = b^{mn} rewrites the same function for a different step, and the new factor shows the new rate.

From years to months. An account grows 15%15\% a year, so after tt years it holds P(1.15)tP(1.15)^t. There are 12t12t months in tt years, so split the exponent:

1.15t=(1.151/12)12t≈1.011712t1.15^t = \left(1.15^{1/12}\right)^{12t} \approx 1.0117^{12t}

The monthly factor is about 1.01171.0117: growth of about 1.17%1.17\% a month. That is less than 15÷12=1.25%15 \div 12 = 1.25\%, because monthly growth compounds — each month’s gain earns interest in the months that follow.

From months to years. Growth of 1%1\% a month, over tt years, is 1.0112t1.01^{12t}. Group the other way:

1.0112t=(1.0112)t≈1.1268t1.01^{12t} = \left(1.01^{12}\right)^t \approx 1.1268^t

That is about 12.68%12.68\% a year, more than the 12%12\% a quick multiplication suggests.

Reading a half-life. A 200200-milligram dose that halves every 66 hours leaves 200(0.5)t/6200(0.5)^{t/6} milligrams after tt hours. The exponent t6\tfrac{t}{6} counts half-lives. Per hour:

0.5t/6=(0.51/6)t≈0.891t0.5^{t/6} = \left(0.5^{1/6}\right)^t \approx 0.891^t

The body clears about 10.9%10.9\% of what remains each hour.

Common mistakes

Practice problems

  1. Is “$40 a week” linear or exponential?

    Answer

    Linear

    Full solution

    A fixed amount added each step.

  2. Is “grows 6%6\% a year” linear or exponential?

    Answer

    Exponential

    Full solution

    A fixed percent means a fixed multiplier.

  3. Outputs run 5,10,20,405, 10, 20, 40. Which model?

    Answer

    Exponential, b=2b = 2

    Full solution

    Each output is twice the one before it.

  4. Outputs run 9,14,19,249, 14, 19, 24. Which model?

    Answer

    Linear

    Full solution

    The difference is 55 every step.

  5. For y=80⋅2xy = 80 \cdot 2^x, what is the value at x=0x = 0?

    Answer

    8080

    Full solution

    20=12^0 = 1, so the start value is aa.

  6. For y=500⋅1.04xy = 500 \cdot 1.04^x, what is the percent growth per step?

    Answer

    4%4\%

    Full solution

    b=1+rb = 1 + r, so r=0.04r = 0.04.

  7. What is bb for a 20%20\% loss per step?

    Answer

    0.80.8

    Full solution

    Losing 20%20\% keeps 80%80\%.

  8. Write the function for $400 growing 10%10\% per year, and find its value after 33 years.

    Hint

    Convert the percent to a multiplier first.

    Answer

    y=400⋅1.1xy = 400 \cdot 1.1^x, giving $532.40

    Full solution

    A 10%10\% rise gives b=1.10b = 1.10, and the start value is 400400.

    y=400⋅1.1xy = 400 \cdot 1.1^x.

    At x=3x = 3: 1.13=1.3311.1^3 = 1.331, so 400×1.331=532.40400 \times 1.331 = 532.40.

  9. A line is y=100xy = 100x and a curve is y=2xy = 2^x. Which is larger at x=5x = 5, and which at x=20x = 20?

    Answer

    The line at x=5x = 5; the curve at x=20x = 20

    Full solution

    At x=5x = 5: the line gives 500500 and the curve gives 3232.

    At x=20x = 20: the line gives 2,0002{,}000 and the curve gives 1,048,5761{,}048{,}576.

    A steep line leads at first, and the exponential passes it once the doubling has enough to work on.

  10. A $300 item loses 25%25\% of its value a year. Asked for its value after 22 years, Jo answers $150, because 25%25\% of 300300 is 7575 and two years is 150150 off. Find the error.

    Hint

    Is the second year’s 25%25\% taken from the same amount as the first year’s?

    Answer

    Jo used a fixed dollar amount. The value is $168.75.

    Full solution

    A percent loss is taken from the current value, not the original one, so the dollar amount falls each year.

    Year 1: 25%25\% of 300300 is 7575, leaving 225225.

    Year 2: 25%25\% of 225225 is 56.2556.25, leaving 168.75168.75.

    As a function: b=1−0.25=0.75b = 1 - 0.25 = 0.75, so y=300⋅0.75xy = 300 \cdot 0.75^x, and 300×0.5625=168.75300 \times 0.5625 = 168.75.

    Jo’s method takes 7575 off twice, which would be right for “loses $75 a year” — a linear situation, and a different one.

  11. A town’s population is modeled by P=8000(1.2)t/10P = 8000(1.2)^{t/10}, with tt in years. What is the growth rate per decade, and what is it per year?

    Hint

    Rewrite 1.2t/101.2^{t/10} as a power of tt alone.

    Answer

    20%20\% per decade, and about 1.84%1.84\% per year.

    Full solution

    The exponent t10\tfrac{t}{10} counts decades, and the factor per decade is 1.21.2, so the town grows 20%20\% every ten years.

    For the yearly factor, move the 110\tfrac{1}{10} onto the base: 1.2t/10=(1.21/10)t≈1.0184t1.2^{t/10} = \left(1.2^{1/10}\right)^t \approx 1.0184^t.

    The yearly factor is about 1.01841.0184, or 1.84%1.84\% a year — not 2%2\%, because ten years of compounding at 1.84%1.84\% already produce the full 20%20\%.

Frequently asked questions

What makes a function exponential?

The variable is in the exponent. Each step multiplies the output by the same factor, instead of adding the same amount.

How do I spot it in a table?

Divide consecutive outputs. A constant ratio means exponential. A constant difference means linear.

What do a and b mean in y = a·bˣ?

a is the value at x = 0, the starting amount. b is the growth factor — what you multiply by for each step of 1.

What does b less than 1 mean?

Decay. Multiplying by 0.9 each step leaves 90% of what was there, so the amount shrinks.

Does exponential growth always win?

Eventually, yes. Any exponential with b greater than 1 passes any straight line, however steep, if you go far enough.

What to learn next

Standards alignment

This lesson covers the following Common Core State Standards for Mathematics.

  • CCSS.MATH.CONTENT.HSF.LE.A.1Linear, Quadratic, and Exponential ModelsDistinguish between situations that can be modeled with linear functions and with exponential functions.
  • CCSS.MATH.CONTENT.HSF.LE.A.1aLinear, Quadratic, and Exponential ModelsProve that linear functions grow by equal differences over equal intervals, and that exponential functions grow by equal factors over equal intervals.
  • CCSS.MATH.CONTENT.HSF.LE.A.1bLinear, Quadratic, and Exponential ModelsRecognize situations in which one quantity changes at a constant rate per unit interval relative to another.
  • CCSS.MATH.CONTENT.HSF.LE.A.1cLinear, Quadratic, and Exponential ModelsRecognize situations in which a quantity grows or decays by a constant percent rate per unit interval relative to another.
  • CCSS.MATH.CONTENT.HSF.LE.A.3Linear, Quadratic, and Exponential ModelsObserve using graphs and tables that a quantity increasing exponentially eventually exceeds a quantity increasing linearly, quadratically, or (more generally) as a polynomial function.
  • CCSS.MATH.CONTENT.HSF.IF.C.8bInterpreting FunctionsUse the properties of exponents to interpret expressions for exponential functions.
  • CCSS.MATH.CONTENT.HSA.SSE.B.3cSeeing Structure in ExpressionsUse the properties of exponents to transform expressions for exponential functions.