Statistics & Probability · Grades 6

Mean, Median and Mode: The Three Averages

Quick answer

The mean is the total divided by how many values there are. The median is the middle value once they are in order. The mode is the value that appears most often. All three are called averages, and they can differ widely on the same data — an outlier drags the mean towards it while leaving the median where it was, which is why the median is used for house prices and salaries.

What you'll learn

  • Calculate the mean, median and mode of a data set
  • Explain what each measure of center describes
  • Choose the better measure when the data contains an outlier

Three ways to describe the middle

All three are called averages. Each summarises a whole data set with one number, and each does it differently.

MeasureHow to find it
meanadd everything, divide by how many
medianput in order, take the middle
modethe value that appears most

Take the test scores 6,7,7,9,116, 7, 7, 9, 11.

mean=6+7+7+9+115=405=8\text{mean} = \frac{6 + 7 + 7 + 9 + 11}{5} = \frac{40}{5} = 8 median=6,7,7,9,11    7\text{median} = 6, 7, \mathbf{7}, 9, 11 \;\Rightarrow\; 7 mode=7(it appears twice)\text{mode} = 7 \quad (\text{it appears twice})

Three different answers from one data set, and none of them is wrong.

The mean shares the total out evenly

mean=sum of the valuesnumber of values\text{mean} = \frac{\text{sum of the values}}{\text{number of values}}

The mean answers: if everyone had the same amount, how much would that be? Five students scoring 4040 marks between them average 88 each.

That also explains why the mean need not be a value anyone actually got. The mean of 44 and 77 is 5.55.5, and the mean number of children per family is famously not a whole number.

The median needs the data in order

Sorting first is not optional. The median of 9,2,59, 2, 5 is 55, and reading the middle of the unsorted list would give 22.

With an odd count there is one middle value:

3,5,8,9,12    median=83, 5, \mathbf{8}, 9, 12 \;\Rightarrow\; \text{median} = 8

With an even count there are two, so take their mean:

3,5,8,9,12,15    8+92=8.53, 5, \mathbf{8}, \mathbf{9}, 12, 15 \;\Rightarrow\; \frac{8 + 9}{2} = 8.5

Why the choice between them matters

Here are the salaries at a small company, in thousands:

28,  30,  31,  32,  34,  35,  35028, \; 30, \; 31, \; 32, \; 34, \; 35, \; 350
Salaries at a small company, in thousands A dot plot with six dots clustered between 28 and 35, and a single dot far out at 350. The gap between the cluster and the lone value takes up most of the axis. 0 50 100 150 200 250 300 350
Salaries at a small company, in thousands
mean=540777median=32\text{mean} = \frac{540}{7} \approx 77 \qquad \text{median} = 32

The mean salary is 7777 thousand. Nobody earns anywhere near that. Six of the seven people earn under 3636, and the seventh earns 350350.

That single value is an outlier, and it drags the mean up by more than 4545 thousand while moving the median not at all. The mean uses every value, so an extreme one has extreme influence. The median only cares about position, so a value ten times too big counts exactly as much as a value slightly too big — it is one entry above the middle either way.

This is why house prices, salaries and household incomes are reported as medians. A few very large values are normal in that data, and the mean would describe none of the people in it.

DataBetter measureBecause
test scores, similar rangemeanuses all the information
salaries, house pricesmedianresists outliers
shoe sizes, favourite colourmodethe most common value is the useful one

The mode is the only one that must be a real value

The mode is the value appearing most often, and a data set can have:

  • one mode: 2,3,3,52, 3, 3, 5 has mode 33
  • two modes: 2,2,5,5,82, 2, 5, 5, 8 has modes 22 and 55
  • no mode: 1,4,7,91, 4, 7, 9 — every value appears once

Mode is also the only average that works for data that is not numbers. There is no mean favourite colour, but there is a most common one.

Worked examples

Common mistakes

Practice problems

  1. Find the mean of 2,5,82, 5, 8.

    Answer

    55

    Full solution

    2+5+83=153=5\tfrac{2 + 5 + 8}{3} = \tfrac{15}{3} = 5.

  2. Find the median of 7,2,9,4,67, 2, 9, 4, 6.

    Answer

    66

    Full solution

    In order: 2,4,6,7,92, 4, 6, 7, 9. The middle of five values is the third, which is 66.

  3. Find the mode of 3,5,5,7,9,9,93, 5, 5, 7, 9, 9, 9.

    Answer

    99

    Full solution

    99 appears three times, more than any other value.

  4. Find the median of 12,4,8,2012, 4, 8, 20.

    Hint

    An even count.

    Answer

    1010

    Full solution

    In order: 4,8,12,204, 8, 12, 20. The two middle values are 88 and 1212, so the median is 8+122=10\tfrac{8 + 12}{2} = 10.

  5. Find the mean of 10,12,14,1610, 12, 14, 16.

    Answer

    1313

    Full solution

    524=13\tfrac{52}{4} = 13.

  6. Five numbers have a mean of 1212. What is their total?

    Answer

    6060

    Full solution

    The mean is the total divided by 55, so the total is 12×5=6012 \times 5 = 60.

  7. Six numbers have a mean of 77. Five of them are 4,5,7,9,104, 5, 7, 9, 10. Find the sixth.

    Answer

    77

    Full solution

    The total must be 7×6=427 \times 6 = 42. The five known values add to 3535, so the sixth is 4235=742 - 35 = 7.

  8. Find the mean and median of 3,4,4,5,643, 4, 4, 5, 64.

    Answer

    Mean 1616, median 44

    Full solution

    Mean: 805=16\tfrac{80}{5} = 16. Median: the middle of the sorted five values is 44.

    The 6464 is an outlier, which is why the two differ so much.

  9. A set has no mode. What does that tell you?

    Answer

    Every value appears the same number of times, usually once each.

    Full solution

    The mode is whichever value appears most often. If no value appears more than any other, nothing stands out and the set has no mode.

  10. A class of 1010 has a mean test score of 7070. A student who scored 100100 is removed. Find the new mean.

    Hint

    Work with the total, not the mean.

    Answer

    About 66.766.7

    Full solution

    The total for 1010 students is 70×10=70070 \times 10 = 700.

    Removing the 100100 leaves 600600 across 99 students:

    600966.7\tfrac{600}{9} \approx 66.7.

    The mean falls because the removed score was above it. Removing a score below the mean would have raised it — which is worth noticing, since it explains why the mean moves at all when the data set changes size.

Frequently asked questions

How do I find the mean?

Add all the values, then divide by how many there are. For 4, 6 and 11 the total is 21 and there are 3 values, so the mean is 7.

How do I find the median?

Put the values in order and take the middle one. With an even count there is no single middle, so take the mean of the two middle values.

What is the mode?

The value that appears most often. A set can have more than one mode, or none at all if every value appears once.

When should I use the median instead of the mean?

When the data has an outlier. One very large or very small value pulls the mean towards it, while the median barely moves.

Can the mean be a value that is not in the data?

Yes, and usually it is. The mean of 4 and 7 is 5.5, which is neither of them. The mode is the only one of the three that has to be an actual data value.

What to learn next

Key terms in this lesson

Mean
The mean is the total of the values divided by how many there are. It shares the total out evenly, so it need not equal any value in the data, and a single outlier can pull it a long way.
Median
The median is the middle value once the data is in order. With an even count it is the mean of the two middle values. Because it depends on position rather than size, an outlier barely moves it.
Outlier
An outlier is a value far from the rest of the data. It pulls the mean towards itself and inflates the range, while leaving the median and interquartile range almost untouched.

Standards alignment

This lesson covers the following Common Core State Standards for Mathematics.

  • CCSS.MATH.CONTENT.6.SP.A.2Statistics and ProbabilityUnderstand that a set of data collected to answer a statistical question has a distribution which can be described by its center, spread, and overall shape.
  • CCSS.MATH.CONTENT.6.SP.A.3Statistics and ProbabilityRecognize that a measure of center for a numerical data set summarizes all of its values with a single number, while a measure of variation describes how its values vary with a single number.
  • CCSS.MATH.CONTENT.6.SP.B.5cStatistics and ProbabilityGiving quantitative measures of center (median and/or mean) and variability (interquartile range and/or mean absolute deviation), as well as describing any overall pattern and any striking deviations from the overall pattern with reference to the context in which the data were gathered.